发布于2021-03-07 19:18 阅读(835) 评论(0) 点赞(18) 收藏(5)
Consider:
$a = 'How are you?';
if ($a contains 'are')
echo 'true';
Suppose I have the code above, what is the correct way to write the statement if ($a contains 'are')
?
You can use the strpos()
function which is used to find the occurrence of one string inside another one:
$a = 'How are you?';
if (strpos($a, 'are') !== false) {
echo 'true';
}
Note that the use of !== false
is deliberate (neither != false
nor === true
will return the desired result); strpos()
returns either the offset at which the needle string begins in the haystack string, or the boolean false
if the needle isn't found. Since 0 is a valid offset and 0 is "falsey", we can't use simpler constructs like !strpos($a, 'are')
.
Edit:
Now with PHP 8 you can do this:
if (str_contains('How are you', 'are')) {
echo 'true';
}
作者:黑洞官方问答小能手
链接:http://www.phpheidong.com/blog/article/96/1960be31709200b40b18/
来源:php黑洞网
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